# Scala downwards or decreasing for loop?

In Scala, you often use an iterator to do a for loop in an increasing order like:

```for(i <- 1 to 10){ code }
```

How would you do it so it goes from 10 to 1? I guess 10 to 1 gives an empty iterator (like usual range mathematics)?

I made a Scala script which solves it by calling reverse on the iterator, but it's not nice in my opinion, is the following the way to go?

```def nBeers(n:Int) = n match {

case 0 => ("No more bottles of beer on the wall, no more bottles of beer." +
"\nGo to the store and buy some more, " +
"99 bottles of beer on the wall.\n")

case _ => (n + " bottles of beer on the wall, " + n +
" bottles of beer.\n" +
"Take one down and pass it around, " +
(if((n-1)==0)
"no more"
else
(n-1)) +
" bottles of beer on the wall.\n")
}

for(b <- (0 to 99).reverse)
println(nBeers(b))
```

```scala> 10 to 1 by -1
res1: scala.collection.immutable.Range = Range(10, 9, 8, 7, 6, 5, 4, 3, 2, 1)
```

The answer from @Randall is good as gold, but for sake of completion I wanted to add a couple of variations:

```scala> for (i <- (1 to 10).reverse) {code} //Will count in reverse.

scala> for (i <- 10 to(1,-1)) {code} //Same as with "by", just uglier.
```

Scala provides many ways to work on downwards in loop.

1st Solution: with "to" and "by"

```//It will print 10 to 0. Here by -1 means it will decremented by -1.
for(i <- 10 to 0 by -1){
println(i)
}
```

2nd Solution: With "to" and "reverse"

```for(i <- (0 to 10).reverse){
println(i)
}
```

3rd Solution: with "to" only

```//Here (0,-1) means the loop will execute till value 0 and decremented by -1.
for(i <- 10 to (0,-1)){
println(i)
}
```

Having programmed in Pascal, I find this definition nice to use:

```implicit class RichInt(val value: Int) extends AnyVal {
def downto (n: Int) = value to n by -1
def downtil (n: Int) = value until n by -1
}
```

Used this way:

```for (i <- 10 downto 0) println(i)
```

You can use Range class:

```val r1 = new Range(10, 0, -1)
for {
i <- r1
} println(i)
```

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