Why does python `any` return a bool instead of the value?

and and or return the last element they evaluated, but why doesn't Python's built-in function any?

I mean it's pretty easy to implement oneself like this, but I'm still left wondering why.

def any(l):
    for x in l:
        if x:
            return x
    return x

edit:

To add to the answers below, here's an actual quote from that same mailing list of ye mighty emperor on the issue:

Whether to always return True and False or the first faling / passing element? I played with that too before blogging, and realized that the end case (if the sequence is empty or if all elements fail the test) can never be made to work satisfactory: picking None feels weird if the argument is an iterable of bools, and picking False feels weird if the argument is an iterable of non-bool objects.

Guido van Rossum (home page: http://www.python.org/~guido/)

Answers


This very issue came up up on the Python developer's mailing list in 2005, when Guido Van Rossum proposed adding any and all to Python 2.5.

Bill Janssen requested that they be implemented as

def any(S):
    for x in S:
        if x:
            return x
    return S[-1]

def all(S):
    for x in S:
        if not x:
            return x
    return S[-1]

Raymond Hettinger, who implemented any and all, responded specifically addressing why any and all don't act like and and or:

Over time, I've gotten feedback about these and other itertools recipes. No one has objected to the True/False return values in those recipes or in Guido's version.

Guido's version matches the normal expectation of any/all being a predicate. Also, it avoids the kind of errors/confusion that people currently experience with Python's unique implementation of "and" and "or".

Returning the last element is not evil; it's just weird, unexpected, and non-obvious. Resist the urge to get tricky with this one.

The mailing list largely concurred, leaving the implementation as you see it today.


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