Subtract date which is retrieve from mysql database by 2 days using PHP

I want to take date which should be before 2 days of expiry date. I am getting Expiry date from MYSQL database. Here is my code:

$result=mysql_query("SELECT * from assets");


echo "Start date:".$row["start_date"];

echo "Expiry date:".$row["expiry_date"];


$date=date('Y-m-d',strtotime('+2 days', $expdate));

echo "2 Days before Expiry date:".$date;


But I am getting output like this:

Start date:2012-05-01

Expiry date:2012-06-30

2 Days before Expiry date:1970-01-03 

Can you help me please?


The 2nd argument of PHP's strtotime() function expects a Unix timestamp. Try this instead:

$date=date('Y-m-d',strtotime($expdate.' +2 days'));

The strtotime function takes two parameters

int strtotime ( string $time [, int $now = time() ] )

The second should be an integer, but it looks like you are passing it a string. You need to convert it to an integer first. This should work:

$expdate_int = strtotime($expdate);
$date = date('Y-m-d', strtotime('+2 days', $expdate_int));

If appropriate, you could also look at doing the date maths in SQL

SELECT expdate, DATE_SUB(expdate, INTERVAL 2 DAY) AS two_days_before_exp

You have asked for a day which is 2 days before expiry day .

  $date=date('Y-m-d',strtotime($expdate.'-2 days'));

strtotime('+2 days', $expdate)

Second argument must be a timestamp

Change your following line

$date=date('Y-m-d',strtotime('+2 days', $expdate));

to following

$date=date('Y-m-d',strtotime('-2 days', strtotime($expdate)));

strtotime second parameter expects timestamp (not a string date). "-2" to make it 2 days before.

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