Exception in Thread:must be a sequence, not instance

Im working on python and im trying to execute a thread that takes 1 parameter "q", but when im trying to execute it a strange exception occurs, here's my code:

class Workspace(QMainWindow, Ui_MainWindow):
    """ This class is for managing the whole GUI `Workspace'.
        Currently a Workspace is similar to a MainWindow
    """

    def __init__(self):

        try:
            from Queue import Queue, Empty
        except ImportError:
    #from queue import Queue, Empty  # python 3.x
            print "error"

        ON_POSIX = 'posix' in sys.builtin_module_names

        def enqueue_output(out, queue):
            for line in iter(out.readline, b''):
                queue.put(line)
            out.close()

        p= Popen(["java -Xmx256m -jar bin/HelloWorld.jar"],cwd=r'/home/karen/sphinx4-1.0beta5-src/sphinx4-1.0beta5/',stdout=PIPE, shell=True, bufsize= 4024)
        q = Queue()

        t = threading.Thread(target=enqueue_output, args=(p.stdout, q))
        #t = Thread(target=enqueue_output, args=(p.stdout, q))

        t.daemon = True # thread dies with the program
        t.start()

# ... do other things here
        def myfunc(q):
            while True:

                try: line = q.get_nowait()
         # or q.get(timeout=.1)
                except Empty:
                    print('')
                else: # got line
    # ... do something with line
                    print "No esta null"
                    print line  


        thread = threading.Thread(target=myfunc, args=(q))
        thread.start()

It fails with the following error:

Exception in thread Thread-2:
Traceback (most recent call last):
  File "/usr/lib/python2.7/threading.py", line 551, in __bootstrap_inner
    self.run()
  File "/usr/lib/python2.7/threading.py", line 504, in run
    self.__target(*self.__args, **self.__kwargs)
TypeError: myfunc() argument after * must be a sequence, not instance

I dont have idea what is happening! Help please!

Answers

The args parameter to threading.Thread should be a tuple and you are passing (q) which is not - it is the same as q.

I guess you wanted a 1-element tuple: you should would write (q,).

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