How to copy boost python list or his reference with "=" operator

take this code

#include<boost/python>
namespace bp = boost::python;

bp::list py_points; //initial list
other_class* C; // this class have a bp::list attribute called py_list

// ... some code ....

// in this part C.py_list.ptr() is 0x0

other_class->py_list = py_list; // problem here!!

the problem is with the operator "="

in the debugger in the object_core.hpp file, this is a boost python core file

inline api::object_base& api::object_base::operator=(api::object_base const& rhs)
{
    Py_INCREF(rhs.m_ptr);
    Py_DECREF(this->m_ptr); // in this line the program fail
    this->m_ptr = rhs.m_ptr;
    return *this;
}

what is the proper way to use the operator "="

edited

the problem is the stack, if the pointer other_class->py_list is null (or None because the class constructor is not called) the program can´t call the función Py_DECREF (Don't exist references before of the NULL pointer)

the problem is fix calling the constructor

other_class* C = new othe_class(); // fixed!!

Answers


The problem is not the assignment operator, the problem is that py_list's internal PyObject pointer is a nullptr. In the majority of cases, the pointer should not be null. From a Python point of view, it should at least manage a reference to the Python None object, as it done by a default constructed boost::python::object. The default constructor for boost::python::list creates a new empty list. Hence, the source of the problem likely resides within either other_class's constructor or the "some code" block.


To elaborate on the question posed within the title, creating a reference or copying list in Boost.Python is the same as in Python:

  • The assignment operator will create a reference to a list.

    >>> a = ['spam']
    >>> b = a
    >>> b
    ['spam']
    >>> a is b
    True
    
  • One can slice a list to create a shallow copy.

    >>> a = ['spam']
    >>> b = a[:]
    >>> b
    ['spam']
    >>> a is b
    False
    

Here is a complete example with the Python equivalent code annotated in the comments.

#include <iostream>
#include <boost/python.hpp>

/// @brief Mockup class.
struct other_class
{
  boost::python::list py_list;
};

/// @brief Helper function to print object id and its string representation.
std::string to_string(boost::python::object& o)
{
  std::stringstream stream;
  stream << o.ptr() << " = "
         << boost::python::extract<std::string>(o.attr("__str__")())();
  return stream.str();
}

int main()
{
  using std::cout;
  using std::endl;
  namespace python = boost::python;

  Py_Initialize();
  try
  {
    python::object object;                            // object = None
    cout << to_string(object) << "\n"                 // print object
         << "  is none check: " << object.is_none()   // print object is None
         << endl;

    // Create other_class and populate its list.
    other_class* c = new other_class();               // py_list = []
    cout << "c->py_list: " << to_string(c->py_list)   // print py_list
         << endl;
    c->py_list.append("spam");                        // py_list.append("spam")
    cout << "c->py_list: " << to_string(c->py_list)   // print py_list
         << endl;

    // Have list1 reference c->py_list.
    python::list list1;                                // list1 = []
    cout << "list1: " << to_string(list1) << "\n"      // print list1
         << "assign py_list to list1" << endl;
    list1 = c->py_list;                                // list1 = py_list
    cout << "list1: " << to_string(list1) << endl;     // print list1

    // Modify list1 and observe effects on pylist.
    cout << "modify list1" << endl;
    list1.append(42);                                 // list1.append(42)
    cout << "c->py_list: " << to_string(c->py_list)   // print py_list
         << endl;

    // Shallow-copy list1.
    cout << "copying list1 into list2" << endl;
    python::list list2(
        list1.slice(python::_, python::_));            // list2 = list1[:]
    list2.append("eggs");                              // list2.append("eggs")
    cout << "list2: " << to_string(list2) << "\n"      // print list2
         << "list1: " << to_string(list1) << endl;     // print list1

    delete c;
  }
  catch (python::error_already_set&)
  {
    PyErr_Print();
  }
}

Output:

0x804e1ac = None
  is none check: 1
c->py_list: 0xb707024c = []
c->py_list: 0xb707024c = ['spam']
list1: 0xb70da98c = []
assign py_list to list1
list1: 0xb707024c = ['spam']
modify list1
c->py_list: 0xb707024c = ['spam', 42]
copying list1 into list2
list2: 0xb707cb0c = ['spam', 42, 'eggs']
list1: 0xb707024c = ['spam', 42]

A few points to note in the output:

  • Default constructed boost::python::list objects manage a reference to an empty list. 0x804e1ac is None, and none of the list object's internal PyObject pointer manage a reference to it.
  • The list1 = py_list assignment causes list1 to manage a reference to the same list managed by py_list. This is exhibited in the output by list1 initially managing a reference to 0xb70da98c, but post-assignment, it manages a reference to 0xb707024c. With list1 and py_list managing the same list, a change to the list through one handle can be observed in the other handle.
  • Slicing constructed a new list. Thus, the PyObject internal point for list2 manages a different reference (0xb707cb0c) than list1's pointer (0xb707024c).

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