MYSQLI errors - help in search syntax - JOIN

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Answers


Please try the following query:

SELECT t1.*, t2.Name

FROM
(

  SELECT * FROM ClientCodes WHERE (nextCheck<'$timer') LIMIT $start,5

) AS t1

JOIN Clientlist AS t2 

ON t1.ClientNumber = t2.Clientnumber

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Single Sign On for Web Application and Application in Virtual Directory

.net authentication virtual-directory single-sign-on machinekey

To enable single sign-on for a web application and a web application in a virtual directory, I set the machinekey in both apps to the same: