Regex - match to obtain words before and after \r\n

Why doesn't my regex match?

SOURCE[\s]*[:]*[\s]*(\r\n|\r|\n)*[\[#x3000\]]*[A-Za-z \!\.\-]*


\xa0SOURCE:\r\nHult International Business School\r\n\r\n\r\n\r\n\r\nSUBJECT: ENTREPRENEURSHIP (92%); 

My regex tries. it seems to work nearly okay here.

For some reason, only a [\s] captured the \r\n. i don't understand why. using [\s]* solved it.


Is your regex pattern defined with a raw string? If so, it should match:

In [25]: import re

In [26]: text = '\xa0SOURCE:\r\nHult International Business School\r\n\r\n\r\n\r\n\r\nSUBJECT: ENTREPRENEURSHIP (92%);'

In [27]:'SOURCE[\s]*[:]*[\s]*(\r\n|\r|\n)*[\[#x3000\]]*[A-Za-z \!\.\-]*', text)
Out[27]: <_sre.SRE_Match at 0xb0bffa0>

From the docs:

Raw string notation (r"text") keeps regular expressions sane. Without it, every backslash ('\') in a regular expression would have to be prefixed with another one to escape it.

Missing some escaping?

SOURCE[\s]*[:]*[\s]*(\\r\\n|\\r|\\n)*[\[#x3000\]]*[A-Za-z \!\.\-]*

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