MySQL query to calculate percentage of total column
How to convert this result:
Group | Sum Services | 11120.99 Vendas | 3738.00
Group | Sum Services | 74.84 Vendas | 25.16
That is, the second displays the results as percentages of total.
This is what I tried:
SELECT categories.cat AS 'Group', SUM(atual) AS 'Sum' FROM `table1` INNER JOIN categories ON table1.category_id=categories.id GROUP BY categoria
you can left join a total sum that is not grouped or split up, and divide that by your sum query. this way you are just doing the total select once for faster runtime
SELECT cat, sum_atual, sum_atual/total_atual as percent_atual FROM ( SELECT categories.cat AS cat, SUM(atual) AS sum_atual FROM `table1` JOIN categories ON table1.category_id=categories.id GROUP BY categoria ) t LEFT JOIN ( SELECT SUM(atual) as total_atual FROM `table1` ) t1
SELECT categories.cat AS categoria, SUM(atual) * 100 / (select sum(atual) from table1) AS percentages FROM `table1` INNER JOIN categories ON table1.category_id=categories.id GROUP BY categoria
You can do this several ways. One is to just use a subquery in the select clause. As written below, this assumes that the category_id column in table1 always matches categories:
SELECT c.categoria AS "Group", SUM(t1.atual) AS "Sum", SUM(t1.atual) / (SELECT SUM(t1.atual) FROM table1) as "Percent" FROM `table1` t1 INNER JOIN categories c ON t1.category_id = c.id GROUP BY c.categoria;
I changed the group by clause as well. It is a good idea for the group by and select to use the same columns. And I added table aliases to all the column references, another good practice.