Extra argument 'selector' in call - NSTimer scheduledTimerWithTimeInterval

I have the following line of code:

changeColour = NSTimer.scheduledTimerWithTimeInterval(TIMES, target: self, selector: "changeColourOfPage", repeats: true)

but it gives the error "Extra argument 'selector' in call"

when I change the TIMES variable to a number like 1.0, it works fine. The variable TIMES is set to 1.0.

Is this just a glitch, or am I being stupid about something? I need to use it to run a method at random intervals.

Please help!

Answers


It looks like you're missing the userInfo argument. Try this:

Swift 2

let TIMES = 1.0
var changeColour = NSTimer.scheduledTimerWithTimeInterval(TIMES, target: self, selector: "restart", userInfo: nil, repeats: true)

Swift 3, 4, 5

let TIMES = 1.0
var changeColour = Timer.scheduledTimer(timeInterval: TIMES, target: self, selector: #selector(restart), userInfo: nil, repeats: true)

Just had this same issue. For me the problem was that I was passing a time interval as a Float not a Double. Simple fix was (using the code from the original post):

NSTimer.scheduledTimerWithTimeInterval(Double(TIMES), target: self, selector: Selector("changeColourOfPage"), userInfo:nil, repeats: true)

I had the same error message and once I cast the time as a Double it worked fine. Hope that helps someone!


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