MATLAB - extracting rows of a matrix
a = [1 2; 3 4; 5 6] I want to extract the first and third row of a, so I have x = [1; 3] (indices of rows).
a(x) doesn't work.
Like this: a([1,3],:)
The comma separates the dimensions, : means "entire range", and square brackets make a list.
In MATLAB if one parameter is given when indexing, it is so-called linear indexing. For example if you have 4x3 matrix, the linear indices of the elements look like this, they are growing by the columns:
1 5 9 2 6 10 3 7 11 4 8 12
Because you passed the [1 3] vector as a parameter, the 1st and 3rd elements were selected only.
When selecting whole columns or rows, the following format shall be used:
A(:, [list of columns]) % for whole columns A([list of rows], :) % for whole rows
General form of 2d matrix indexing:
A([list of rows], [list of columns])
The result is the elements in the intersection of the indexed rows and columns. Results will be the elements marked by X:
A([2 4], [3 4 5 7]) . . C C C . C R R X X X R X . . C C C . C R R X X X R X
Reference and some similar examples: tutorial on MATLAB matrix indexing.
x = a([1 3]) behaves like this:
temp = a(:) % convert matrix 'a' into a column wise vector x = temp([1 3]) % get the 1st and 3rd elements of 'a'
you could write a loop to iterate across the rows of the matrix:
for i = [1,3] a(i,:) end
type this: a([1 3],[1 2]) the output is
ans = 1 2 5 6