like this

```range = (0..10)
```

how can I get number like this:

```0 5 10
```

plus five every time but less than 10

if range = (0..20) then i should get this:

```0 5 10 15 20
```

Try using .step() to go through at a given step.

```(0..20).step(5) do |n|
print n,' '
end
```

gives...

```0 5 10 15 20
```

As mentioned by dominikh, you can add .to_a on the end to get a storable form of the list of numbers: (0..20).step(5).to_a

Like Dav said, but add to_a:

```(0..20).step(5).to_a # [0, 5, 10, 15, 20]
```

The step method described in http://ruby-doc.org/core/classes/Range.html should do the job but seriously harms may harm the readability.

Just consider:

```(0..20).step(5){|n| print ' first ', n }.each{|n| print ' second ',n }
```

You may think that step(5) kind of produces a new Range, like why_'s question initially intended. But the each is called on the (0..20) and has to be replaced by another step(5) if you want to "reuse" the 0-5-10-15-20 range.

Maybe you will be fine with something like (0..3).map{|i| i*5}?

But "persisting" the step method's results with .to_a should also work fine.