# Android Matrix, what does getValues() return?

i'm having trouble working out the returned values of the below code pMeasure = PathMeasure, m = Matrix, distCount is the distance along the path

```pMeasure.getMatrix(distCount, m, 0x01 | 0x02);
m.getValues(float[] values)
```

float & float are position x & y respectively but i can't figure out the rest

any help once again appreciated.

## Answers

Taken from the Matrix class documentation:

public static final int MPERSP_0 Constant Value: 6 (0x00000006)

public static final int MPERSP_1 Constant Value: 7 (0x00000007)

public static final int MPERSP_2 Constant Value: 8 (0x00000008)

public static final int MSCALE_X Constant Value: 0 (0x00000000)

public static final int MSCALE_Y Constant Value: 4 (0x00000004)

public static final int MSKEW_X Constant Value: 1 (0x00000001)

public static final int MSKEW_Y Constant Value: 3 (0x00000003)

public static final int MTRANS_X Constant Value: 2 (0x00000002)

public static final int MTRANS_Y Constant Value: 5 (0x00000005)

Android Matrix uses skia and its row-major meaning the indices are as follows

```0  1  2
3  4  5
6  7  8
```

I contrast OpenGL uses indices like so

```0  3  6
1  4  7
2  5  8
```

The "meanings" are identical in regards to matrix position.

```a  b  tx
c  d  ty
0  0   1
```

a,b,c,d encode scale & rotation at the same time. tx/ty encode translation. If you do m.getValues(vals); then vals == tx, vals == ty, and the rest is straight forward. The best way to extract translation is to make a vector

```float[] point = {0, 0};
```

Then map it and see where it ends up and that's your translation (which is exactly (tx, ty). Under rare circumstances its not

to get scale map a second point

```float[] point2 = {1, 0};
```

Now take the difference rel = (point - point2) and get the length of that vector and that's your scale. To extract rotation, normalize rel and it's simple to get it's standard angle.

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